【Cypher】Room1 隱寫術(shù)(上半)
Room1:Steganography? (隱寫術(shù))
此房間一共有8個(gè)謎題請根據(jù)題目給出猜測得到的信息


STEGANOGRAPHY
Stegenography (concealed writing)is a form?of?cryptography whereby a secret message is hidden?within another innocuous looking message,with the?hope that it will pass undetected
Steganography is a weak form of cryotography as?the secret message is not enciphered and relies?entirely on its ability to go unnoticed.Once a hidden?message is suspected it can usually be revealed?without the need of any special techniques,?given?enough time and scrutiny.
When cryptanalysing a text you should begin by looking closely for any unusual aspects of the text such as alignment,spacing,word choice,etc, which Indicates the text has been forced into some pattem.Secondly you should look for altemate ways of interpreting the message aside from the obvious.
隱寫術(shù)
隱寫術(shù)(隱寫)是一種密碼學(xué),其中一個(gè)秘密信息隱藏在另一個(gè)看起來無害的信息中,希望它能不被發(fā)現(xiàn)地通過
隱寫術(shù)是比較weak的一種方式,因?yàn)槊孛苄畔]有被加密,完全依賴于它不被發(fā)現(xiàn)的能力。一旦懷疑有隱藏的信息,只要有足夠的時(shí)間和仔細(xì)的審查,通常不需要任何特殊的技術(shù)就能把它暴露出來。
當(dāng)對文本進(jìn)行密碼分析時(shí),您應(yīng)該首先仔細(xì)檢查文本的任何不尋常方面,如對齊、間距、單詞選擇等,這表明文本已被迫進(jìn)入某種模式。其次,除了顯而易見的信息,你應(yīng)該尋找其他解釋信息的方法。
謎題一:

以下是解法:

觀察每句話的首字母,可得:spysuspected
謎題二:

以下是解法:
(這段文字來自艾倫-坡的一首詩'The Raven'?)
Once upon a midnight dreary, while I pondered, weak and weary
Over many a quaint and curious volume of forgotten lore
While I nodded, nearly napping, suddenly there came a tapping
As of some one rapping, rapping at my chamber door
"'Tis some visitor," I muttered, "tapping at my chamber door--
Only this, and nothing more."
經(jīng)過對比,可以看出有幾個(gè)單詞拼寫是錯(cuò)誤的,是
while? ??forgotten? ? suddenly? ? door? ?? muttered? ? chamber
whille? ?foregotten? ?suddenly? ?dooor? ? ?mutterred? chambere

多出來的字母合成一個(gè)單詞:lenore
(這題設(shè)計(jì)得很巧妙呀!lenore是愛倫坡《Lenore》中的已逝少女,是愛倫坡已逝嬌妻弗吉尼亞的化身,《The Raven》(烏鴉)中的已逝少女。)
謎題三:

以下是解法:

湊近放大了看...有很淡很淡的字跡......(??)
謎題四:

以下是解法:
仔細(xì)觀察文字,可以看出有些文字區(qū)分與其它文字(斜體),找出來發(fā)現(xiàn)是:
too? ? one? ? for? ? free
利用讀音,too和two同音,for和four同音,free發(fā)音相近于three
所以可以得出:“2? 1? 4? 3”
(待續(xù)......