LeetCode 1566. Detect Pattern of Length M Repeated K or More Tim
Given an array of positive integers?arr
, find a pattern of length?m
?that is repeated?k
?or more times.
A?pattern?is a subarray (consecutive sub-sequence) that consists of one or more values, repeated multiple times?consecutively?without overlapping. A pattern is defined by its length and the number of repetitions.
Return?true
?if there exists a pattern of length?m
?that is repeated?k
?or more times, otherwise return?false
.
?
Example 1:
Input: arr = [1,2,4,4,4,4], m = 1, k = 3
Output: true
Explanation: The pattern (4) of length 1 is repeated 4 consecutive times. Notice that pattern can be repeated k or more times but not less.
Example 2:
Input: arr = [1,2,1,2,1,1,1,3], m = 2, k = 2
Output: true
Explanation: The pattern (1,2) of length 2 is repeated 2 consecutive times. Another valid pattern (2,1) is also repeated 2 times.
Example 3:
Input: arr = [1,2,1,2,1,3], m = 2, k = 3
Output: false
Explanation: The pattern (1,2) is of length 2 but is repeated only 2 times. There is no pattern of length 2 that is repeated 3 or more times.
?
Constraints:
2 <= arr.length <= 100
1 <= arr[i] <= 100
1 <= m <= 100
2 <= k <= 100
主要就是理解題意,連續(xù)重復(fù)的數(shù)量,
依次遍歷累加就行了。
下面是代碼;
Runtime:?0 ms, faster than?100.00%?of?Java?online submissions for?Detect Pattern of Length M Repeated K or More Times.
Memory Usage:?40.7 MB, less than?30.71%?of?Java?online submissions for?Detect Pattern of Length M Repeated K or More Times.