自動匹配系統(tǒng)指令,下期視頻更新自動分隊

首先拿出盔甲架和命名牌,并把命名牌命名為匹配中,在來到盔甲架旁邊點擊名稱
一·基礎(chǔ)指令
1.輸入/give @s command_block 評論區(qū)
2./scoreboard objectives add 倒計時 dummy 評論區(qū)
3./scoreboard objectives add 人數(shù) dummy 評論區(qū)
二,第一組命令方塊{共三個}分別是循環(huán)無條件保持,連鎖無條件保持開啟,連鎖無條件保持,備注:dx,dy,dz以及xyz自己改
1./scoreboard players set @e[type=armor_stand,name=匹配中] 人數(shù) 0
2./execute @a[x=-882,y=64,z=-106,dx=-18,dy=15,dz=-18]~~~scoreboard players add @e[type=armor_stand,name=匹配中] 人數(shù) 1
3./titleraw @a[x=-882,y=64,z=-106,dx=-18,dy=15,dz=-18] actionbar {"rawtext":[{"text":"§l§9匹配中§f|§4目前人數(shù)§b"},{"score":{"name":"@e[type=armor_stand,name=匹配中]","objective":"人數(shù)"}},{"text":"§f/10"},{"text":"\n§e倒計時§b "},{"score":{"name":"@e[type=armor_stand,name=匹配中]","objective":"倒計時"}}]}
三·第三組指令 循環(huán)無條件保持,其余連鎖無條件保持
1./scoreboard players set @e[name=匹配中,scores={人數(shù)=0..1},type=armor_stand] 倒計時 60
2./scoreboard players set @e[name=匹配中,scores={人數(shù)=3..,倒計時=21..},type=armor_stand] 倒計時 20
3./scoreboard players set @e[name=匹配中,scores={人數(shù)=8..,倒計時=11..},type=armor_stand] 倒計時 10
4./execute @e[name=匹配中,scores={倒計時=0},type=armor_stand]~~~ title @a[x=-882,y=64,z=-106,dx=-18,dy=15,dz=-18] title §l§a游戲開始
5./execute @e[name=匹配中,scores={倒計時=0},type=armor_stand]~~~tp @a[x=-882,y=64,z=-106,dx=-18,dy=15,dz=-18] -722 63 -144
四·共兩個命令方塊 循環(huán)無條件保持 延遲15 第二個連鎖有條件保持。有!有!有!
1./scoreboard players remove @e[type=armor_stand,name=匹配中,scores={人數(shù)=2..}] 倒計時 1
2./execute @e[type=armor_stand,name=匹配中,scores={倒計時=0..10}] ~~~playsound random.orb @a[x=-882,y=64,z=-106,dx=-18,dy=15,dz=-18]
指令結(jié)束,合作加微:15801655697