視頻BV18V411t7nU解析
令x2=t
f(t)=(at+b)/(ct+d)
a/c≠b/d
t≥0
若-d/c>0
則f(t)分別在
[0,-d/c)與(-d/c,+∞)連續(xù)且單調(diào)
且t→-d/c,f(t)→∞
t→+∞,f(t)→a/c
f(0)=b/d
故
若b/d<a/c
f(t)值域為(-∞,b/d]∪(a/c,+∞)
若b/d>a/c
f(t)值域為(-∞,a/c)∪[b/d,+∞)
令x2=t
f(t)=(at+b)/(ct+d)
a/c≠b/d
t≥0
若-d/c>0
則f(t)分別在
[0,-d/c)與(-d/c,+∞)連續(xù)且單調(diào)
且t→-d/c,f(t)→∞
t→+∞,f(t)→a/c
f(0)=b/d
故
若b/d<a/c
f(t)值域為(-∞,b/d]∪(a/c,+∞)
若b/d>a/c
f(t)值域為(-∞,a/c)∪[b/d,+∞)
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