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[Fluid Mechanics] Venturimeter

2021-11-09 09:41 作者:AoiSTZ23  | 我要投稿

By: Tao Steven Zheng(鄭濤)

【Problem】

Consider an ideal fluid of density %5Crho flowing through a horizontal pipe of variable cross-sectional area. The fluid at the portion of the pipe with cross-sectional area %7BA%7D_%7B1%7D is moving at %7Bv%7D_%7B1%7D and has a measured pressure of %7BP%7D_%7B1%7D. The fluid at the portion of the pipe with cross-sectional area %7BA%7D_%7B2%7D is moving at %7Bv%7D_%7B2%7D and has a measured pressure of %7BP%7D_%7B2%7D.

Part 1: Determine %7Bv%7D_%7B1%7D in terms of %5Crho%2C%20A_1%2C%20A_2%2C%20P_1%2C%20P_2.

Part 2: Two different fluids of density %7B%5Crho%7D_%7B1%7D%20 (fluid in the horizontal pipe) and %7B%5Crho%7D_%7B2%7D%20 (fluid in the u-shaped manometer), where %7B%5Crho%7D_%7B1%7D%20%3C%20%7B%5Crho%7D_%7B2%7D. The height difference of the fluid in the manometer is %20h%20. It helps to let h%20%3D%20h_1%20-%20h_2. Determine %7Bv%7D_%7B1%7D in terms of %7B%5Crho%7D_%7B1%7D%2C%20%7B%5Crho%7D_%7B2%7D%2C%20A_1%2C%20A_2%2C%20h.

【Solution】

Part 1
There are two important equations for this problem:

1) The continuity equation
%5Crho%20A_1%20v_1%20%3D%20%5Crho%20A_2%20v_2

2) Bernoulli’s equation
%20P_1%20%2B%20%5Crho%20gh_1%20%2B%20%5Cfrac%7B1%7D%7B2%7D%20%5Crho%20v_1%5E2%20%3D%20P_2%20%2B%20%5Crho%20gh_2%2B%5Cfrac%7B1%7D%7B2%7D%20%5Crho%20v_2%5E2%20

From the first equation we find

v_2%20%3D%20%5Cfrac%7BA_1%20v_1%7D%7BA_2%7D%20

Since there is no change in the altitude of the pipe; hence,

P_1%20%2B%20%5Cfrac%7B1%7D%7B2%7D%20%5Crho%20v_1%5E2%20%3D%20P_2%20%2B%20%5Cfrac%7B1%7D%7B2%7D%20%5Crho%20%5Cleft(%5Cfrac%7BA_1%20v_1%7D%7BA_2%7D%20%5Cright)%5E2%20

Isolate for v_1:

P_1%20-%20P_2%20%3D%20%5Cfrac%7B1%7D%7B2%7D%20%5Crho%20v_1%5E2%20%5Cleft%5B%5Cleft(%5Cfrac%7BA_1%7D%7BA_2%7D%20%5Cright)%5E2-1%5Cright%5D


v_1%20%3D%20%5Csqrt%7B%5Cfrac%7B2(P_1-P_2)%7D%7B%5Crho%20%5Cleft%5B%5Cleft(%5Cfrac%7BA_1%7D%7BA_2%7D%5Cright)%5E2-1%20%5Cright%5D%7D%7D%20


Part 2

Treat the manometer as two static column problems.

P_1%20%2B%20%7B%5Crho%7D_%7B1%7D%20g%20h_1%20%3D%20P_2%20%2B%20%7B%5Crho%7D_%7B1%7D%20g%20h_2%20%2B%20%7B%5Crho%7D_%7B2%7D%20g%20(h_1%20-%20h_2)%20

P_1%20-%20P_2%20%3D%20-%7B%5Crho%7D_%7B1%7D%20g%20h_1%20%2B%20%7B%5Crho%7D_%7B1%7D%20g%20h_2%20%2B%20%7B%5Crho%7D_%7B2%7D%20g%20(h_1%20-%20h_2)%20

P_1%20-%20P_2%20%3D%20(%7B%5Crho%7D_%7B2%7D%20-%20%7B%5Crho%7D_%7B1%7D)%20g%20(h_1%20-%20h_2)%20

P_1%20-%20P_2%20%3D%20(%7B%5Crho%7D_%7B2%7D%20-%20%7B%5Crho%7D_%7B1%7D)%20gh%20


Substitute the difference of pressure into the result from part 1 to get

v_1%20%3D%20%5Csqrt%7B%5Cfrac%7B2(%7B%5Crho%7D_%7B2%7D%20-%20%7B%5Crho%7D_%7B1%7D)gh%7D%7B%7B%5Crho%7D_%7B1%7D%20%5Cleft%5B%7B%5Cleft(%5Cfrac%7BA_1%7D%20%7BA_2%7D%5Cright)%7D%5E%7B2%7D%20-%201%20%5Cright%5D%7D%7D




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