視頻 BV1Sh411y7r6 解析
令
f(x)
=1/(x+(a-2))+1/(x+(a-1))+1/(x+a)
1/(x+(a+1))+1/(x+(a+2))
則
f(-a+x)
=1/(x-2)+1/(x-1)+1/x
1/(x+1)+1/(x+2)
f(-a-x)
=-1/(x+2)-1/(x+1)-1/x
-1/(x-1)-1/(x-2)
即(f(-a+x)+f(-a-x))/2=0
即f(x)關(guān)于點(diǎn)(-a,0)中心對(duì)稱
令
g(x)
=1/(x+(a-2))+1/(x+(a-1))+1/(x+a)
1/(x+(a+1))+1/(x+(a+2))+1/(x+a+3)
則
g(-(2a+1)/2+x)
=1/(x-5/2)+1/(x-3/2)+1/(x-1/2)
1/(x+1/2)+1/(x+3/2)+1/(x+5/2)
g(-(2a+1)/2-x)
=-1/(x+5/2)-1/(x+3/2)-1/(x+1/2)
-1/(x-1/2)-1/(x-3/2)-1/(x-5/2)
即
(g(-(2a+1)/2+x)+g(-(2a+1)/2-x))
/2=0
即g(x)關(guān)于點(diǎn)(-(2a+1)/2,0)中心對(duì)稱
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