You are given two strings?current?and?correct?representing two?24-hour times.

24-hour times are formatted as?"HH:MM", where?HH?is between?00?and?23, and?MM?is between?00?and?59. The earliest 24-hour time is?00:00, and the latest is?23:59.

In one operation you can increase the time?current?by?1,?5,?15, or?60?minutes. You can perform this operation?any?number of times.

Return?the?minimum number of operations?needed to convert?current?to?correct.

?

Example 1:

Input: current = "02:30", correct = "04:35"

Output: 3

Explanation:

We can convert current to correct in 3 operations as follows: - Add 60 minutes to current. current becomes "03:30". - Add 60 minutes to current. current becomes "04:30". - Add 5 minutes to current. current becomes "04:35". It can be proven that it is not possible to convert current to correct in fewer than 3 operations.

Example 2:

Input: current = "11:00", correct = "11:01"

Output: 1

Explanation: We only have to add one minute to current, so the minimum number of operations needed is 1.

?

Constraints:

• current?and?correct?are in the format?"HH:MM"

• current <= correct

主要是寫2個函數(shù)，一個是將小時轉(zhuǎn)換成分鐘，這樣所有的數(shù)據(jù)都是用分鐘去判斷，

剩下就是判斷調(diào)整的次數(shù)，用while循環(huán)即可；（我沒看完題目，這里面current是一定小于correct的，但是代碼里面是加了一層判斷的）

下面是代碼：

Runtime:?1 ms, faster than?94.12%?of?Java?online submissions for?Minimum Number of Operations to Convert Time.

Memory Usage:?40.9 MB, less than?61.03%?of?Java?online submissions for?Minimum Number of Operations to Convert Time.