循環(huán)輸出200到1000之間，

? ?只要能被5整除，或則能被8整除的數(shù)。

#include <stdio.h>?

int main()

{

?int n=200;//初始值

while(n<=1000&&n>=200)?

{if(n%5==0&&n%8==0) {

printf("%d\n",n);

//多個printf時用{}，單個printf時不用{}

}

n++;

}

}

#include <stdio.h>?

int main()

{

int a;

int c;

int n;

a=10;

?c=a*n;

n=1;//初始值

while(n<=10&&n>=1)//若寫成1<=n<=10則編譯錯誤，相當于沒定義范圍，會有死循環(huán)，即會不停出現(xiàn)無數(shù)個數(shù)據(jù)

{

printf("%d*%d=%d",a,n,c);//多個printf時用{}，單個printf時不用{}

n++;//n=n+1，若寫成c++則相當于沒定義n范圍，會有死循環(huán)，即會不停出現(xiàn)無數(shù)個數(shù)據(jù)

}

}

#include <stdio.h>?

int main()

{

? int n=1;//初始值

while(n<=100&&n>=1)?

{if(n%10==0)?

printf("%d\n",n);//多個printf時用{}，單個printf時不用{}

n++;//n=n+1

}

}

#include <stdio.h>?

int main()

{

int result,n;

result=0;

? ?n=1;

?//初始值

while(n<=100)?

{result+=n;

n=n+1;//n++

}

printf("%d",result);

}

#include <stdio.h>?

int main()

{

int n1=0;

int n2=1;

while(n2<=100)?

{

printf("%d+%d=%d\n",n1,n2,(n1+n2));

n1=n1+n2;

n2++;

}

}

#include <stdio.h>?

int main()

{

int n1=0;

int n2=1;

while(n2<=100)?

{

printf("%d+%d=%d\n",n1,n2,(n1+n2));

n1=n1+n2;

n2=n2+2;//n2+=2

}

}

#include <stdio.h>?

int main()

{

? int n=10;//初始值

while(n<=100&&n>=10)?

{if(n%5==0) {

printf("%d\n",n);//多個printf時用{}，單個printf時不用{}

}

n++;

}

}

#include <stdio.h>?

int main()

{

?int n=100;//初始值

while(n<=200&&n>=100)?

{if(n%2==0&&n%3==0) {

printf("%d\n",n);

//多個printf時用{}，單個printf時不用{}

}

n++;

}

}