Leetcode 2383. Minimum Hours of Training to Win a Competition
You are entering a competition, and are given two?positive?integers?initialEnergy
?and?initialExperience
?denoting your initial energy and initial experience respectively.
You are also given two?0-indexed?integer arrays?energy
?and?experience
,
both of length?n
.
You will face?n
?opponents?in order.?
The energy and experience of the?ith
?opponent is denoted by?energy[i]
?and?experience[i]
?respectively.
When you face an opponent, you need to have both?strictly?greater experience and energy to defeat them and move to the next opponent if available.
Defeating the?ith
?opponent?increases?your experience by?experience[i]
, but?decreases?your energy by?energy[i]
.
Before starting the competition,?
you can train for some number of hours.?
After each hour of training, you can?either?choose to increase your initial experience by one, or increase your initial energy by one.
Return?the?minimum?number of training hours required to defeat all?n
?opponents.
?
Example 1:
Input: initialEnergy = 5, initialExperience = 3, energy = [1,4,3,2], experience = [2,6,3,1]
Output: 8
Explanation: You can increase your energy to 11 after 6 hours of training,?
and your experience to 5 after 2 hours of training.?
You face the opponents in the following order:?
- You have more energy and experience than the 0th opponent so you win. ?
Your energy becomes 11 - 1 = 10,?
and your experience becomes 5 + 2 = 7.
- You have more energy and experience than the 1st opponent so you win. ?
Your energy becomes 10 - 4 = 6, and your experience becomes 7 + 6 = 13.?
- You have more energy and experience than the 2nd opponent so you win. ?
Your energy becomes 6 - 3 = 3, and your experience becomes 13 + 3 = 16.?
- You have more energy and experience than the 3rd opponent so you win.?
?Your energy becomes 3 - 2 = 1, and your experience becomes 16 + 1 = 17.?
You did a total of 6 + 2 = 8 hours of training before the competition, so we return 8. It can be proven that no smaller answer exists.
Example 2:
Input: initialEnergy = 2, initialExperience = 4, energy = [1], experience = [3]Output: 0Explanation:?
You do not need any additional energy or experience to win the competition, so we return 0.
?
Constraints:
n == energy.length == experience.length
1 <= n <= 100
1 <= initialEnergy, initialExperience, energy[i], experience[i] <= 100
一開(kāi)始理解錯(cuò)意思了,其實(shí)就是按順序即可,另一個(gè)就是每次計(jì)算出差異,hours累加。
Runtime:?0 ms, faster than?100.00%?of?Java?online submissions for?Minimum Hours of Training to Win a Competition.
Memory Usage:?41.9 MB, less than?41.15%?of?Java?online submissions for?Minimum Hours of Training to Win a Competition.