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拉格朗日函數(shù),對(duì)偶函數(shù),(凸)共軛函數(shù)

2023-06-28 11:37 作者:師翊  | 我要投稿

考慮一個(gè)最優(yōu)化問(wèn)題:

%5Cbegin%7Barray%7D%7Bl%7D%7B%5Coperatorname*%7Bmin%7D~f(x)%7D%5C%5C%20%7Bs.t.~l_%7Bi%7D(x)%5Cleqslant0%7D%26%7Bi%3D1%2C...%2Cm%7D%5C%5C%5Cqquad%7Bh_%7Bj%7D(x)%3D0%7D%26%7Bj%3D1%2C...%2Cn%7D%5C%5C%20%5Cend%7Barray%7D

該最優(yōu)化問(wèn)題的定義域:

D%3D%5Ctext%7Bdom%7Df%5Cleft(%20x%20%5Cright)%20%5Ccap%20%5Ctext%7Bdom%7Dl_i%5Cleft(%20x%20%5Cright)%20%5Ccap%20%5Ctext%7Bdom%7Dh_i%5Cleft(%20x%20%5Cright)%20

上述問(wèn)題的拉格朗日函數(shù)為:

L%5Cleft(%20x%2C%5Clambda%20%2C%5Cmu%20%5Cright)%20%3Df_0%5Cleft(%20x%20%5Cright)%20%2B%5Csum_%7Bi%3D1%7D%5Em%7B%5Clambda%20_il_i%7D%5Cleft(%20x%20%5Cright)%20%2B%5Csum_%7Bj%3D1%7D%5En%7B%5Cmu%20_j%7Dh_j%5Cleft(%20x%20%5Cright)%20

該問(wèn)題的對(duì)偶函數(shù)為:

g%5Cleft(%20%5Clambda%20%2C%5Cmu%20%5Cright)%20%3D%5Cunderset%7Bx%5Cin%20D%7D%7B%5Ctext%7Binf%7D%7DL%5Cleft(%20x%2C%5Clambda%20%2C%5Cmu%20%5Cright)%20%3D%5Cunderset%7Bx%5Cin%20D%7D%7B%5Ctext%7Binf%7D%7D%5Cleft%5C%7B%20f%5Cleft(%20x%20%5Cright)%20%2B%5Csum_%7Bi%3D1%7D%5Em%7B%5Clambda%20_il_i%5Cleft(%20x%20%5Cright)%20%2B%5Csum_%7Bj%3D1%7D%5En%7B%5Cmu%20_ih_i%5Cleft(%20x%20%5Cright)%7D%7D%20%5Cright%5C%7D

f(x)的(凸)共軛函數(shù)的定義為:

f%5E*%5Cleft(%20y%20%5Cright)%20%3D%5Cunderset%7Bx%5Cin%20%5Ctext%7Bdom%7Df%7D%7B%5Ctext%7Bsup%7D%7D%5Cleft(%20y%5ETx-f%5Cleft(%20x%20%5Cright)%20%5Cright)%20%3D-%5Cunderset%7Bx%5Cin%20%5Ctext%7Bdom%7Df%7D%7B%5Ctext%7Binf%7D%7D%5Cleft(%20f%5Cleft(%20x%20%5Cright)%20-y%5ETx%20%5Cright)%20

下面推導(dǎo)共軛函數(shù)和對(duì)偶函數(shù)的關(guān)系。首先將約束條件矩陣化,考慮如下最優(yōu)化問(wèn)題:

%5Cmin%5Ctext%7B%20%7Df%5Cleft(%20%5Cboldsymbol%7Bx%7D%20%5Cright)%20%0A%5C%5Cs.t.%5C%20%5Cboldsymbol%7BAx%7D%5Cle%20%5Cboldsymbol%7Bb%7D%0A%0A%5C%20%5C%20%5C%20%5C%20%5C%5C%5Cboldsymbol%7BCx%7D%3D%5Cboldsymbol%7Bd%7D

其對(duì)偶函數(shù)為:

g%5Cleft(%20%5Cboldsymbol%7B%5Clambda%20%2C%5Cmu%20%7D%20%5Cright)%20%3D%5Cunderset%7Bx%5Cin%20D%7D%7B%5Ctext%7Binf%7D%7D%5C%7Bf%5Cleft(%20%5Cboldsymbol%7Bx%7D%20%5Cright)%20%2B%5Cboldsymbol%7B%5Clambda%20%7D%5ET%5Cleft(%20%5Cboldsymbol%7BAx%7D-%5Cboldsymbol%7Bb%7D%20%5Cright)%20%2B%5Cboldsymbol%7B%5Cmu%20%7D%5ET%5Cleft(%20%5Cboldsymbol%7BCx%7D-%5Cboldsymbol%7Bd%7D%20%5Cright)%20%5C%7D%0A%5C%5C%3D%5Cunderset%7Bx%5Cin%20D%7D%7B%5Ctext%7Binf%7D%7D%5Cleft%5C%7B%20f%5Cleft(%20%5Cboldsymbol%7Bx%7D%20%5Cright)%20%2B%5Cleft(%20%5Cboldsymbol%7BA%7D%5ET%5Cboldsymbol%7B%5Clambda%20%7D%2B%5Cboldsymbol%7BC%7D%5ET%5Cboldsymbol%7B%5Cmu%20%7D%20%5Cright)%20%5ET%5Cboldsymbol%7Bx%7D%20%5Cright%5C%7D%20-%5Cboldsymbol%7B%5Clambda%20%7D%5ET%5Cboldsymbol%7Bb%7D-%5Cboldsymbol%7B%5Cmu%20%7D%5ET%5Cboldsymbol%7Bd%7D%0A%5C%5C%3D%5Cunderset%7Bx%5Cin%20D%7D%7B%5Ctext%7Binf%7D%7D%5Cleft%5C%7B%20f%5Cleft(%20%5Cboldsymbol%7Bx%7D%20%5Cright)%20-%5Cleft(%20-%5Cboldsymbol%7BA%7D%5ET%5Cboldsymbol%7B%5Clambda%20%7D-%5Cboldsymbol%7BC%7D%5ET%5Cboldsymbol%7B%5Cmu%20%7D%20%5Cright)%20%5ET%5Cboldsymbol%7Bx%7D%20%5Cright%5C%7D%20-%5Cboldsymbol%7B%5Clambda%20%7D%5ET%5Cboldsymbol%7Bb%7D-%5Cboldsymbol%7B%5Cmu%20%7D%5ET%5Cboldsymbol%7Bd%7D%0A%5C%5C%5Ctext%7B%E8%A7%82%E5%AF%9F%E5%AF%B9%E5%81%B6%E5%87%BD%E6%95%B0%E5%AE%9A%E4%B9%89%EF%BC%8C%E5%8D%B3%E4%B8%8A%E5%BC%8F%E4%B8%AD%7D%5Cleft(%20-%5Cboldsymbol%7BA%7D%5ET%5Cboldsymbol%7B%5Clambda%20%7D-%5Cboldsymbol%7BC%7D%5ET%5Cboldsymbol%7B%5Cmu%20%7D%20%5Cright)%20%5Ctext%7B%E6%98%AF%E5%AF%B9%E5%81%B6%E5%87%BD%E6%95%B0%E4%B8%AD%E7%9A%84%7Dy%0A%5C%5C%3D-f%5E*%5Cleft(%20-%5Cboldsymbol%7BA%7D%5ET%5Cboldsymbol%7B%5Clambda%20%7D-%5Cboldsymbol%7BC%7D%5ET%5Cboldsymbol%7B%5Cmu%20%7D%20%5Cright)%20-%5Cboldsymbol%7B%5Clambda%20%7D%5ET%5Cboldsymbol%7Bb%7D-%5Cboldsymbol%7B%5Cmu%20%7D%5ET%5Cboldsymbol%7Bd%7D%0A

因此對(duì)偶函數(shù)可以通過(guò)共軛函數(shù)表示。而共軛函數(shù)又可以通過(guò)原函數(shù)表示。那么共軛函數(shù)將對(duì)偶函數(shù)和原函數(shù)連接起來(lái)。





拉格朗日函數(shù),對(duì)偶函數(shù),(凸)共軛函數(shù)的評(píng)論 (共 條)

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