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[Mechanics] Block on a Ramp

2021-07-26 22:32 作者:AoiSTZ23  | 我要投稿

By: Tao Steven Zheng (鄭濤)

【Problem】

The above free-body diagram illustrates a block of mass?m that is stationary on a ramp (inclined plane). The angle of inclination is %5Calpha, and the coefficient of static friction is %7B%5Cmu%7D_%7Bs%7D.

Part 1: Identify the forces?F_1%2C%20F_2%2C%20F_3%20 in the free-body diagram.

Part 2: Determine the formula for calculating the largest angle in which the block will remain stationary.

Part 3: If the coefficient of static friction is 0.8, what is the maximum angle %5Calpha%20?


【Solution】

Part 1

F_1%20?is the gravitational force F_g.

F_2 is the normal force F_N.

F_3 is the static friction force %7BF%7D_%7Bfs%7D.


Part 2

Organize the forces in this problem in two directions: perpendicular to the ramp and parallel to the ramp. Then write the equations of motion %7BF%7D_%7Bnet%7D%20%3D%20ma in each direction. Note that the gravitational force needs to be resolved into each component; the perpendicular component is %7BF%7D_%7Bg%5Cperp%7D%20%3D%20mg%5Ccos%7B(%5Calpha)%7D. The parallel component is %7BF%7D_%7Bg%5Cparallel%7D%20%3D%20mg%5Csin%7B(%5Calpha)%7D%20.

Perpendicular forces

%20%7BF%7D_%7Bnet%5Cperp%7D%20%3D%20m%7Ba%7D_%7B%5Cperp%7D%20

F_N%20-%20%7BF%7D_%7Bg%5Cperp%7D%20%3D%20m%7Ba%7D_%7B%5Cperp%7D%20


Since the block is stationary in the perpendicular direction, the acceleration in the perpendicular direction is zero.


F_N%20-%20F_g%20%5Ccos%7B(%5Calpha)%7D%20%3D%200

Thus,

F_N%20%3D%20mg%20%5Ccos%7B(%5Calpha)%7D

Parallel forces

%20%7BF%7D_%7Bnet%20%5Cparallel%7D%20%3D%20m%7Ba%7D_%7B%5Cparallel%7D


%20%7BF%7D_%7Bfs%7D%20-%20%7BF%7D_%7Bg%5Cparallel%7D%20%3D%20m%7Ba%7D_%7B%5Cparallel%7D%20

Since the block is also stationary in the parallel direction, the acceleration in the parallel direction is zero.


%7BF%7D_%7Bfs%7D%20-%20F_g%20%5Csin%7B(%5Calpha)%7D%20%3D%200%20

The maximum static friction is calculated using the formula

%7BF%7D_%7Bfs%7D%20%3D%20%7B%5Cmu%7D_%7Bs%7D%20F_n

Thus,

%7B%5Cmu%7D_%7Bs%7D%20mg%20%5Ccos%7B(%5Calpha)%7D%20%3D%20mg%20%5Csin%7B(%5Calpha)%7D%20

From this equation

%7B%5Cmu%7D_%7Bs%7D%20%20%3D%20%5Cfrac%7B%5Csin%7B(%5Calpha)%7D%7D%7B%5Ccos%7B(%5Calpha)%7D%7D

%5Ctan%7B(%5Calpha)%7D%20%20%3D%20%7B%5Cmu%7D_%7Bs%7D

%5Calpha%20%3D%20%7B%5Ctan%7D%5E%7B-1%7D%7B(%7B%5Cmu%7D_%7Bs%7D)%7D


Part 3

If the coefficient of static friction is 0.8,


%5Calpha%20%3D%20%7B%5Ctan%7D%5E%7B-1%7D%7B(0.8)%7D

%5Calpha%20%3D%20%7B38.66%7D%5E%7B%5Ccirc%7D%20

[Mechanics] Block on a Ramp的評論 (共 條)

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