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LeetCode2225. Find Players With Zero or One Losses

2022-11-28 17:40 作者:您是打尖兒還是住店呢  | 我要投稿


You are given an integer array?matches?where?matches[i] = [winneri, loseri]?indicates that the player?winneri?defeated player?loseri?in a match.

Return?a list?answer?of size?2?where:

  • answer[0]?is a list of all players that have?not?lost any matches.

  • answer[1]?is a list of all players that have lost exactly?one?match.

The values in the two lists should be returned in?increasing?order.

Note:

  • You should only consider the players that have played?at least one?match.

  • The testcases will be generated such that?no?two matches will have the?same?outcome.

?

Example 1:

Input: matches = [[1,3],[2,3],[3,6],[5,6],[5,7],[4,5],[4,8],[4,9],[10,4],[10,9]]Output: [[1,2,10],[4,5,7,8]]Explanation:Players 1, 2, and 10 have not lost any matches. Players 4, 5, 7, and 8 each have lost one match. Players 3, 6, and 9 each have lost two matches. Thus, answer[0] = [1,2,10] and answer[1] = [4,5,7,8].

Example 2:

Input: matches = [[2,3],[1,3],[5,4],[6,4]]Output: [[1,2,5,6],[]]Explanation:Players 1, 2, 5, and 6 have not lost any matches. Players 3 and 4 each have lost two matches. Thus, answer[0] = [1,2,5,6] and answer[1] = [].

?

Constraints:

  • 1 <= matches.length <= 105

  • matches[i].length == 2

  • 1 <= winneri, loseri?<= 105

  • winneri?!= loseri

  • All?matches[i]?are?unique.


目前暫時(shí)不要求別的,能過就行,這個(gè)是比較簡單是,使用ArrayList即可,

將對(duì)應(yīng)的隊(duì)伍篩選出來即可,包括set,在用collections排序一下就行。

Runtime:?204 ms, faster than?61.77%?of?Java?online submissions for?Find Players With Zero or One Losses.

Memory Usage:?168.4 MB, less than?23.65%?of?Java?online submissions for?Find Players With Zero or One Losses.


LeetCode2225. Find Players With Zero or One Losses的評(píng)論 (共 條)

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