{"ops":[{"attributes":{"class":"normal-img"},"insert":{"native-image":{"alt":"read-normal-img","url":"https://b2.sanwen.net/b_article/watermark/196566a729394d3c30c705b806417dab6e83b891.jpg","width":1078,"height":297,"size":87951,"status":"loaded"}}},{"insert":"第一問分類討論較為繁瑣，關(guān)鍵在于注意到x=lna是一個極值點(diǎn)，解答略去。\n第二問利用第一問結(jié)論可知t=lna＞1，代入后采用先猜后證的證明方法\n"},{"attributes":{"class":"normal-img"},"insert":{"native-image":{"alt":"read-normal-img","url":"https://b2.sanwen.net/b_article/watermark/f06219ce185ec89a2cb80713dee1dee165ad196b.jpg","width":1980,"height":784,"size":242846,"status":"loaded"}}},{"attributes":{"color":"#00aeec"},"insert":"藍(lán)字部分為分析過程。注意到端點(diǎn)處（x=1）原函數(shù)與導(dǎo)函數(shù)的值都等于零，則端點(diǎn)處二階導(dǎo)數(shù)必大于零，解出m的范圍為m≥-e"},{"insert":"\n"},{"attributes":{"color":"#18191c"},"insert":"下對此加以證明"},{"insert":"\n"},{"attributes":{"class":"normal-img"},"insert":{"native-image":{"alt":"read-normal-img","url":"https://b2.sanwen.net/b_article/watermark/c8f7a7d7a9e0cbe17cbc8c34f9570b62fc865396.jpg","width":2060,"height":1548,"size":545294,"status":"loaded"}}},{"insert":"從正反兩個方面進(jìn)行證明，只需討論二階導(dǎo)數(shù)的正負(fù)性即可。\n本題關(guān)鍵在于討論端點(diǎn)特殊情況后加以證明的先猜后證方法，如果直接對含有參數(shù)m的函數(shù)求導(dǎo)討論會比較復(fù)雜。當(dāng)然，藍(lán)色部分的思考過程可以省去，那么卷面上就能呈現(xiàn)出更加簡潔的過程；如果對于后續(xù)證明計算能力信心不足/考試時間不夠了，建議將藍(lán)色思考過程留著得過程分。\n（最后，做出第一小問是最關(guān)鍵的）\n"}]}