倒數(shù)關(guān)系:tanα ·cotα=1sinα ·cscα=1cosα ·secα=1商的關(guān)系:sinα/cosα=tanα=secα/cscαcosα/sinα=cotα=cscα/secα平方關(guān)系:sin^2(α)+cos^2(α)=11+tan^2(α)=sec^2(α)1+cot^2(α)=csc^2(α)