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范德蒙德行列式的推導(dǎo)

2023-06-03 22:01 作者:~Sakuno醬  | 我要投稿

命題

證明?%5Cbegin%7Bvmatrix%7D%0A1%20%26%20x_1%20%26%20x_1%5E2%20%26%20..%20%26x_1%5E%7Bn-1%7D%20%5C%5C%0A1%20%26%20x_2%20%26%20x_2%5E2%20%26%20..%20%26%20x_2%5E%7Bn-1%7D%20%5C%5C%0A..%20%26%20..%20%26%20..%20%26%20..%20%26%20..%20%5C%5C%0A1%20%26%20x_n%20%26%20x_n%5E2%20%26%20..%20%26%20x_n%5E%7Bn-1%7D%20%0A%5Cend%7Bvmatrix%7D 等于?%5Cprod_%7B1%20%5Cle%20i%20%3C%20j%20%5Cle%20n%7D%20(x_j-x_i)

范德蒙德行列式的特點(diǎn)就是第k列的次數(shù)是k-1次,每一列是齊次的

我們的思路是作初等行變換,同時(shí)希望改變后的每一列都是齊次的。


對(duì) n 使用歸納法

假設(shè)?n%3Dk 時(shí)成立

考慮n%3Dk%2B1

%5Cbegin%7Bvmatrix%7D%0A1%20%26%20x_1%20%26%20x_1%5E2%20%26%20..%20%26%20x_1%5E%7Bk-1%7D%20%260%20%5C%5C%0A1%20%26%20x_2%20%26%20x_2%5E2%20%26%20..%20%26%20x_2%5E%7Bk-1%7D%20%26%20x_2%5E%7Bk%7D%20-x_1x_2%5E%7Bk-1%7D%20%5C%5C%0A..%20%26%20..%20%26%20..%20%26%20..%20%26%20..%20%26%20..%20%5C%5C%0A1%20%26%20x_%7Bk%2B1%7D%20%26%20x_%7Bk%2B1%7D%5E2%20%26%20..%20%26%20x_k%5E%7Bk-1%7D%20%26%20x_%7Bk%2B1%7D%5E%7Bk%7D%20-%20x_1x_%7Bk%7D%5E%7Bk-1%7D%0A%5Cend%7Bvmatrix%7D

作初等列變換, 把第k列乘以?-x_1 加到k%2B1

然后是第k-1列乘以-x_1加到k列,繼續(xù)重復(fù)k次,得到

%5Cbegin%7Bvmatrix%7D%0A1%20%26%200%20%26%200%20%26%20..%20%26%200%20%260%20%5C%5C%0A1%20%26%20x_2-x_1%20%26%20x_2%5E2%20-x_1x_2%26%20..%20%26%20x_2%5E%7Bk-1%7D-x_1x_2%5E%7Bk-2%7D%20%26%20x_2%5E%7Bk%7D%20-x_1x_2%5E%7Bk-1%7D%20%5C%5C%0A..%20%26%20..%20%26%20..%20%26%20..%20%26%20..%20%26%20..%20%5C%5C%0A1%20%26%20x_%7Bk%2B1%7D%20-x_1%26%20x_%7Bk%2B1%7D%5E2%20-x_%7B1%7Dx_%7Bk%2B1%7D%26%20..%20%26%20x_k%5E%7Bk-1%7D%20-x_1x_k%5E%7Bk-2%7D%26%20x_%7Bk%2B1%7D%5E%7Bk%7D%20-%20x_1x_%7Bk%7D%5E%7Bk-1%7D%0A%5Cend%7Bvmatrix%7D

根據(jù)行列式的性質(zhì)按第一行展開(kāi)得到

%5Cbegin%7Bvmatrix%7D%0A%20x_2-x_1%20%26%20x_2%5E2%20-x_1x_2%26%20..%20%26%20x_2%5E%7Bk-1%7D-x_1x_2%5E%7Bk-2%7D%20%26%20x_2%5E%7Bk%7D%20-x_1x_2%5E%7Bk-1%7D%20%5C%5C%0A%20x_3-x_1%20%26%20x_3%5E2%20-x_1x_3%26%20..%20%26%20x_3%5E%7Bk-1%7D-x_1x_3%5E%7Bk-2%7D%20%26%20x_3%5E%7Bk%7D%20-x_1x_3%5E%7Bk-1%7D%20%5C%5C%0A..%20%26%20..%20%26%20..%20%26%20..%20%26%20..%20%26%20..%20%5C%5C%0A%20x_%7Bk%2B1%7D%20-x_1%26%20x_%7Bk%2B1%7D%5E2%20-x_%7B1%7Dx_%7Bk%2B1%7D%26%20..%20%26%20x_k%5E%7Bk-1%7D%20-x_1x_k%5E%7Bk-2%7D%26%20x_%7Bk%2B1%7D%5E%7Bk%7D%20-%20x_1x_%7Bk%7D%5E%7Bk-1%7D%0A%5Cend%7Bvmatrix%7D

每一行可以提取公因子?x_2-x_1,x_3-x_1?等

(x_2-x_1)(x_3-x_1)..(x_%7Bk%2B1%7D-x_1)%5Cbegin%7Bvmatrix%7D%0A%201%20%26%20x_2%26%20..%20%26%20x_2%5E%7Bk-2%7D%20%26%20x_2%5E%7Bk-1%7D%20%5C%5C%0A%201%20%26%20x_3%20%26%20..%20%26%20x_3%5E%7Bk-2%7D%20%26%20x_3%5E%7Bk-1%7D%20%5C%5C%0A..%20%26%20..%20%26%20..%20%26%20..%20%26%20..%20%5C%5C%0A%201%26%20x_%7Bk%2B1%7D%26%20..%20%26%20x_k%5E%7Bk-2%7D%26%20x_%7Bk%7D%5E%7Bk-1%7D%0A%5Cend%7Bvmatrix%7D

注意到右邊的行列式是k階的

%3D(x_2-x_1)(x_3-x_1)..(x_%7Bk%2B1%7D-x_1)%5Cprod_%7B2%5Cle%20i%3Cj%5Cle%20k%2B1%7D(x_j-x_i)


%3D%5Cprod_%7B1%20%5Cle%20i%20%3Cj%20%5Cle%20k%2B1%7D(x_j-x_i)



范德蒙德行列式的推導(dǎo)的評(píng)論 (共 條)

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