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盒子

2023-07-11 22:45 作者:忘墨離殤  | 我要投稿

將(無限個(gè)所有宇宙、所有維度、所有空間、所有網(wǎng)絡(luò)世界、所有虛擬世界、所有現(xiàn)實(shí)世界、所有小說、所有故事、書、所有計(jì)劃、所有結(jié)果、所有書、所有一切的可能/不可能、所有全能宇宙、所有多元維度宇宙??而在這些之里面,則又會(huì)有無限無限個(gè)“所有所有宇宙、所有所有維度、所有所有空間、所有所有網(wǎng)絡(luò)世界、所有所有虛擬世界、所有所有現(xiàn)實(shí)世界、所有所有小說、所有所有故事、所有所有書、所有所有計(jì)劃、所有所有結(jié)果、所有所有一切的可能/不可能、所有所有全能宇宙、所有所有多元維度宇宙??與所有概念/所有數(shù)值/所有絕對(duì)無限/所有運(yùn)算/所有可理解/所有不可理解/所有認(rèn)知/所有基數(shù)/所有任何語言無法描述/所有全能宇宙/所有一切/所有知識(shí)/所有數(shù)學(xué)/所有一切/所有真正/所有虛擬/所有現(xiàn)實(shí)/所有全能/超越全能/所有網(wǎng)絡(luò)/所有超越數(shù)學(xué)/所有超越敘事層/所有不可能/所有無法知道/所有無法推測(cè))定義為N(N=阿列夫)(0)=ω 那么便能得到(ω+1 ω+2……ω+ω) ,由此無限循環(huán)疊加得到(1……ω×ω……)=ω^ω,在它的基礎(chǔ)上進(jìn)行(ω^ω)^(ω^ω)^(ω^ω)^(ω^ω)^(ω^ω)^(ω^ω)^(ω^ω)^(ω^ω)^(ω^ω)^(ω^ω)^(ω^ω)^(ω^ω)^(ω^ω)^(ω^ω)^(ω^ω)^(ω^ω)^(ω^ω)^(ω^ω)^(ω^ω)^(ω^ω)^(ω^ω)^(ω^ω)^(ω^ω)^(ω^ω)^(ω^ω)^(ω^ω)^(ω^ω)^(ω^ω)^(ω^ω)^(ω^ω)^(ω^ω)^(ω^ω)^(ω^ω)^(ω^ω)^(ω^ω)^(ω^ω)^(ω^ω)^(ω^ω)^(ω^ω)^(ω^ω)^(ω^ω)^(ω^ω)^(ω^ω)^(ω^ω)^(ω^ω)^(ω^ω)^(ω^ω)^(ω^ω)^(ω^ω)^(ω^ω)^(ω^ω)^(ω^ω)^(ω^ω)^(ω^ω)^(ω^ω)^(ω^ω)^(ω^ω)^(ω^ω)^(ω^ω)^(ω^ω)^(ω^ω)^(ω^ω)^(ω^ω)^(ω^ω)^(ω^ω)^(ω^ω)^(ω^ω)^(ω^ω)^(ω^ω)^(ω^ω)^(ω^ω)^(ω^ω)^(ω^ω)^(ω^ω)^(ω^ω)^(ω^ω)^(ω^ω)^(ω^ω)^(ω^ω)^(ω^ω)^(ω^ω)^(ω^ω)^(ω^ω)^(ω^ω)^(ω^ω)^(ω^ω)^(ω^ω)^(ω^ω)^(ω^ω)^(ω^ω)^......像這樣無限循環(huán),無限疊加,之后得到[(ω^ω×ω^ω)×ω],將上式包括之前的一切一切壓縮為定義(ΨxΨ) 繼續(xù)疊加,無限疊加,無限循環(huán)得到(ΨxΨ)^(ΨxΨ)^(ΨxΨ)^(ΨxΨ)^(ΨxΨ)^(ΨxΨ)^(ΨxΨ)^(ΨxΨ)^(ΨxΨ)^(ΨxΨ)^(ΨxΨ)^(ΨxΨ)^(ΨxΨ)^(ΨxΨ)^(ΨxΨ)^(ΨxΨ)^(ΨxΨ)^(ΨxΨ)^(ΨxΨ)^(ΨxΨ)^(ΨxΨ)^(ΨxΨ)^(ΨxΨ)^(ΨxΨ)^(ΨxΨ)^(ΨxΨ)^(ΨxΨ)^(ΨxΨ)^(ΨxΨ)^(ΨxΨ)^(ΨxΨ)^(ΨxΨ)^(ΨxΨ)^(ΨxΨ)^(ΨxΨ)^(ΨxΨ)^(ΨxΨ)^(ΨxΨ)^(ΨxΨ)^(ΨxΨ)^(ΨxΨ)^(ΨxΨ)^(ΨxΨ)^(ΨxΨ)^(ΨxΨ)^(ΨxΨ)^(ΨxΨ)^(ΨxΨ)^......無盡循環(huán),沒有盡頭,繼續(xù)壓縮上式及上式的上式,定義為(¢↑↑¢),繼續(xù)壓縮,無盡循環(huán),沒有盡頭,(¢↑↑¢)→→(¢↑↑¢)→→(¢↑↑¢)→→(¢↑↑¢)→→(¢↑↑¢)→→(¢↑↑¢)→→(¢↑↑¢)→→(¢↑↑¢)→→(¢↑↑¢)→→(¢↑↑¢)→→(¢↑↑¢)→→(¢↑↑¢)→→(¢↑↑¢)→→(¢↑↑¢)→→(¢↑↑¢)→→(¢↑↑¢)→→(¢↑↑¢)→→(¢↑↑¢)→→(¢↑↑¢)→→(¢↑↑¢)→→(¢↑↑¢)→→(¢↑↑¢)→→(¢↑↑¢)→→(¢↑↑¢)→→(¢↑↑¢)→→(¢↑↑¢)→→(¢↑↑¢)→→(¢↑↑¢)→→(¢↑↑¢)→→(¢↑↑¢)→→(¢↑↑¢)→→(¢↑↑¢)→→(¢↑↑¢)→→(¢↑↑¢)→→(¢↑↑¢)→→(¢↑↑¢)→→(¢↑↑¢)→→(¢↑↑¢)→→(¢↑↑¢)→→(¢↑↑¢)→→(¢↑↑¢)→→(¢↑↑¢)→→......一直重復(fù)循環(huán)到宇宙之緣,回代(NN0=N1)將其按上方式疊加(NN0=N1)?(NN0=N1)?(NN0=N1)?(NN0=N1)?(NN0=N1)?(NN0=N1)?(NN0=N1)?(NN0=N1)?......得到(NN0=N2)?(NN0=N2)?(NN0=N2)?(NN0=N2)?(NN0=N2)?(NN0=N2)?(NN0=N2)?(NN0=N2)?(NN0=N2)?(NN0=N2)?(NN0=N2)?(NN0=N2)?.......得到.......一直到達(dá)(NN0=N不動(dòng)點(diǎn)),設(shè)⊙為可以突然下一不可達(dá)數(shù)的符號(hào)N不動(dòng)點(diǎn)⊙=不可達(dá)基數(shù) 又設(shè)?=⊙循環(huán)疊盒前一個(gè)所達(dá)數(shù)次,1?????????……1,設(shè)⊙包含?,形成閉環(huán),跳過時(shí)間,使Ω 無窮。按上式疊加,在重疊得到(??Ω),繼續(xù)壓縮以上全部的全部,一切的一切,(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)......然后繼續(xù)疊加,(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)......然后繼續(xù)疊加,(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)......然后繼續(xù)疊加,(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)......然后繼續(xù)疊加,(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)......然后繼續(xù)疊加,(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)......然后繼續(xù)疊加,(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)^(??Ω)......如此循環(huán),無限循環(huán),無法停止,永無止境,無論是宇宙破滅還是重塑都無法阻止循環(huán)。

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